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(C) particle comes to rest when its velocity becomes zero.Looking at the velocity-time graph,the velocity $v$ is zero when the graph intersects the ti

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$8$

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(C) particle comes to rest when its velocity becomes zero.Looking at the velocity-time graph,the velocity $v$ is zero when the graph intersects the time axis ($t$-axis).At $t = 0 	ext{ s}$,the velocity is $0 	ext{ m/s}$.At $t = 4.5 	ext{ s}$ (approximately,between $4$ and $5$),the graph crosses the $t$-axis,meaning the velocity is zero.At $t = 8 	ext{ s}$,the velocity is $0 	ext{ m/s}$.Since $4.5 	ext{ s}$ is not among the given options,we check the options provided.Option $A$ $(0 	ext{ s})$ and Option $C$ $(8 	ext{ s})$ are points where the particle is at rest.However,usually,such questions refer to the final state or a specific point of interest. Given the options,$8 	ext{ s}$ is a valid point where the particle is at rest.

The figure shows a velocity-time graph of a particle moving along a straight line. The particle comes to rest at $t = \dots \text{sec}$.

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